x^2+8-5cosx=2sinx

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Solution for x^2+8-5cosx=2sinx equation:


Simplifying
x2 + 8 + -5cosx = 2sinx

Reorder the terms:
8 + -5cosx + x2 = 2sinx

Solving
8 + -5cosx + x2 = 2insx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -5cosx + -8 + x2 = -8 + 2insx

Reorder the terms:
8 + -8 + -5cosx + x2 = -8 + 2insx

Combine like terms: 8 + -8 = 0
0 + -5cosx + x2 = -8 + 2insx
-5cosx + x2 = -8 + 2insx

Add '-1x2' to each side of the equation.
-5cosx + x2 + -1x2 = -8 + 2insx + -1x2

Combine like terms: x2 + -1x2 = 0
-5cosx + 0 = -8 + 2insx + -1x2
-5cosx = -8 + 2insx + -1x2

Divide each side by '-5osx'.
c = 1.6o-1s-1x-1 + -0.4ino-1 + 0.2o-1s-1x

Simplifying
c = 1.6o-1s-1x-1 + -0.4ino-1 + 0.2o-1s-1x

Reorder the terms:
c = -0.4ino-1 + 1.6o-1s-1x-1 + 0.2o-1s-1x

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